(1/16)^3x+4=(128)^2-w

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Solution for (1/16)^3x+4=(128)^2-w equation: 


x in (-oo:+oo)

(1/16)^3*x+4 = 128^2-w // - 128^2-w

w+(1/16)^3*x-128^2+4 = 0

w+1/4096*x-16380 = 0 // - w-16380

1/4096*x = -(w-16380) // : 1/4096

x = (-(w-16380))/1/4096

x = 4096*(16380-w)

x = 4096*(16380-w)

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